Question

plzzzz* help........ ​

Answer 1

$\large{\green{\bold{\underline{Let:}}}}$

$\sf \: The \: five \: numbers \: be \: x, \: x+1, \: x+2, \: x+3 \: and \: x+4$

$\large{\red{\bold{\underline{Then:}}}}$

$\large{\orange{\bold{\underline{According \: To \: Question:}}}}$

$\rightarrow \sf \: x + (x+1) + (x+2) + (x+3) + (x+4) = 270 \\ \\ \rightarrow \sf \: x + x+1 + x+2 + x+3 + x+4 = 270 \\ \\ \rightarrow \sf \: 5x + 10 = 270 \\ \\ \rightarrow \sf \: 5x = 270 - 10 \\ \\ \rightarrow \sf \: 5x = 260 \\ \\ \rightarrow \sf \: x = \frac{ \cancel260}{ \cancel5} \\ \\ \rightarrow \sf \: x = 52$

$\large{\red{\bold{\underline{Then:}}}}$

$\sf \: Numbers \: are \: 52, \: 52+1, \: 52+2, \\ \sf \: 52+3 \: and \: 52+4.$

$\large{\blue{\bold{\underline{Finally:}}}}$

$\sf \: Five \: consecutive \: numbers \: are \: 52, \: 53, \: 54, \\ \sf \: 55 \: and \: 56.$

$\large{\pink{\bold{\underline{But:}}}}$

$\sf \: We \: need \: to \: find \: addition \: of \: 4th \\ \sf \: and \: 3rd \: number.$

$\rightarrow \sf \: 55 + 54 \\ \rightarrow \sf \: 109$

$\large{\green{\bold{\underline{Hence:}}}}$

$\underline{ \underline{ \sf \: The \: required \: Answer \: is \: 109.}}$

Answer 2

Answer:

Solution :-

↦Let, the first number be x

↦ Second number be x + 1

↦ Third number be x + 2

↦ Fourth number be x + 3

↦ Fifth number be x + 4

↦ And, the addition of five consecutive numbers is 270.

According to the question,

⇒ x + x + 1 + x + 2 + x + 3 + x + 4 = 270

⇒ x + x + x + x + x + 1 + 2 + 3 + 4 = 270

⇒ 5x + 10 = 270

⇒ 5x = 270 - 10

⇒ 5x = 260

$⇒</p><p> x = </p><p>\dfrac{260}{5} \:$

➠x=52

Hence, the required numbers are,

✦ First number = x = 52

✦ Second number = x + 1 = 52 + 1 = 53

✦ Third number = x + 2 = 52 + 2 = 54

✦ Fourth number = x + 3 = 52 + 3 = 55

✦ Fifth number = x + 4 = 52 + 4 = 56

But, in question we have to find the addition of second and fifth number,

➳ Second number + Fifth number

➳ 53 + 56

$\implies</p><p>109 \:$

$\huge {\orange {\boxed{ \pink{ \mathscr{hope \: this \: helps \: u}}}}} \:$