Question

plzzzz help............​

Answer 1

$\blue{\texttt{It is given that}}$,

$\blue{\texttt{product of digits }}$ = 18

$\blue{\texttt{lets suppose ten's digit}}$ = x

$\blue{\texttt{so, the unit digit }}$

= $\Large \frac{18}{x}$

Number = 10x +$\Large \frac{18}{x}$

we can get number $\blue{\texttt{by inter changing}}$,

= 10x + $\Large \frac{18}{x}$ +x

$\blue{\texttt{according to the question}}$,

10x +$\Large \frac{18}{x}$-$\Large \frac{180}{x}$-x =63

= 9x - $\Large \frac{162}{x}$=63

= 9 $x^{2}- 63x^{2}$ - 162 = 0

$x^{2}-7x -18 = 0$

$x^{2}-9x - 2x - 18 = 0$

$x (x - 9 ) +2 ( x- 9 ) =0$

$(x - 9 ) ( 2 + x) =0$

$x = 9 \:or x =-2$

$\blue{\texttt{now take x = 9}}$,

$\blue{\texttt{so , the number is }}$,

10x × 9 +$\Large \frac{18}{9}$

$\red{\textbf{ = 92}}$,

$\red{\textbf{hence, the number is 92}}$,