Question

Plzzzz help me....... ​

Answer 1

${\mathfrak{\underline{\purple{\:\:\: Given:-\:\:\:}}}}$

$\:\:\:\:\bullet\:\:\:\sf{Initial \:velocity\: (u) = 0 \:m/s }$

$\:\:\:\:\bullet\:\:\:\sf{Acceleration\: (a) = 4 \:m/s^{2} }$

$\:\:\:\:\bullet\:\:\:\sf{ Time\: (t) = 30\: seconds}$

$\:\:\:\:\bullet\:\:\:\sf{Final \:velocity\: (v) = 0 \:m/s }$

${\mathfrak{\underline{\purple{\:\:\:To \:Find:-\:\:\:}}}}$

$\:\:\:\:\bullet\:\:\:\sf{ Maximum\: velocity \:of \:the \:body}$

${\mathfrak{\underline{\purple{\:\:\: Calculation:-\:\:\:}}}}$

☯ Using 1st equation of motion

$\dashrightarrow\:\: \sf{ v = u + at }$

$\dashrightarrow\:\: \sf{ v_{max} = 0+4\times30 }$

$\dashrightarrow\:\: \sf{ v_{max }= 4\times30 }$

$\dashrightarrow\:\: {\boxed{\sf{ v_{max} = 120 \: m/s}}}$

$\star\:\sf{Maximum\: velocity \:of \:the \:body\:is\:{\bf{120\:m/s}}}$

${\mathfrak{\underline{\purple{\:\:\: Additional \: Information:-\:\:\:}}}}$

☢ Equations Of Motion

$\boxed{</p><p></p><p>\begin{minipage}{3 cm} \\</p><p></p><p>\sf{\:\bullet\:\:v = u +at} \\ \\</p><p></p><p>\sf{\:\bullet\:\:s = ut + \frac{1}{2}\:at^{2} }\\ \\</p><p></p><p>\sf{\:\bullet\:\:v^{2} = u^{2} + 2as}\\ \\</p><p>\sf{\:\bullet\:\:s = \dfrac{1}{2} (u + v)t}\\ </p><p></p><p>\end{minipage}</p><p></p><p>}$

$\sf{Where,}$

$\:\:\:\:\bullet\:\:\:\textsf{v = Final velocity}$

$\:\:\:\:\bullet\:\:\:\textsf{u = Initial velocity}$

$\:\:\:\:\bullet\:\:\:\textsf{a = Acceleration}$

$\:\:\:\:\bullet\:\:\:\textsf{s = Distance}$

$\:\:\:\:\bullet\:\:\:\textsf{t = Time taken}$