Question

Plzzzz help me...... ​

Answer 1

${\mathfrak{\underline{\orange{\:\:\: Given:-\:\:\:}}}}$

$\:\:\:\:\bullet\:\:\:\sf{Acceleration\: (a) = 8 \:m/s^{2}}$

$\:\:\:\:\bullet\:\:\:\sf{Initial\: velocity \:(u) = 0 \:m/s}$

$\:\:\:\:\bullet\:\:\:\sf{Time \:(t) = 1\: seconds}$

${\mathfrak{\underline{\pink{\:\:\:To \:Find:-\:\:\:}}}}$

$\:\:\:\:\bullet\:\:\:\sf{Distance \:travelled \:(s)}$

${\mathfrak{\underline{\purple{\:\:\: Calculation:-\:\:\:}}}}$

☯ Using 2nd equation of motion:-

$\dashrightarrow\:\: \sf{s = ut + \frac{1}{2}a {t}^{2} }$

$\dashrightarrow\:\: \sf{0 \times 1+ \frac{1}{ \cancel2} \times \cancel8 \times 1\times 1}$

$\dashrightarrow\:\: \sf{s = 4\times 1 \times 1}$

$\dashrightarrow\:\: {\boxed{\sf{s = 4\:m}}}$

${\mathfrak{\underline{\red{\:\:\: Additional\: Information:-\:\:\:}}}}$

☣ Equations of motion :-

$\boxed{</p><p></p><p>\begin{minipage}{3 cm} \\</p><p></p><p>\sf{\:\bullet\:\:v = u +at} \\ \\</p><p></p><p>\sf{\:\bullet\:\:s = ut + \frac{1}{2}\:at^{2} }\\ \\</p><p></p><p>\sf{\:\bullet\:\:v^{2} = u^{2} + 2as}\\ \\</p><p>\sf{\:\bullet\:\:s = \dfrac{1}{2} (u + v)t}\\ </p><p></p><p>\end{minipage}</p><p></p><p>}$

$\sf{Where,}$

$\:\:\:\:\bullet\:\:\:\textsf{v = Final velocity}$

$\:\:\:\:\bullet\:\:\:\textsf{u = Initial velocity}$

$\:\:\:\:\bullet\:\:\:\textsf{a = Acceleration}$

$\:\:\:\:\bullet\:\:\:\textsf{s = Distance}$

$\:\:\:\:\bullet\:\:\:\textsf{t = Time taken}$

Answer 2

${\large{\textbf{\underline{\color{skyblue}{Ԛʋᥱꜱtioᥰ \: :-}}}}}$

An object undergoes an acceleration of 8ms −2 starting from rest. Find the distance travelled in 1 second.

${\large{\textbf{\underline{\color{skyblue}{Ꭺnѕwєr \: :-}}}}}$

$\sf \green{Given :-} \\ \sf{Acceleration = 8ms^{ - 2} } \\ \sf{Time = 1 sec} \\ \sf \: Distance \: Travelled, s = ? \\\sf \: Initial \: Velocity , u = 0 \\ \sf \: Using \: the \: equation ; s = ut+1/2at^2 \\\sf \: s = 0 × 1 + 1/2 × 8 × 1^2 = \sf \blue{4meter}.$