Question

plzzzz help me....... ​

Answer 1

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$\large\bf\underline{Given:-}$

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• In Young's double slit experiment if width of slit is made 3 folds

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$\large\bf\underline {To \: find:-}$

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• the fringe width becomes

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$\large\bf\underline{Formula \: Used:-}$

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$\huge \underline{\boxed{ \green{ \bf \: \beta \: \infty \: \frac{1}{d} }}}$

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$\huge\bf\underline{Solution:-}$

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$\sf \longrightarrow \: as \: the \: frnge \: width \: \beta \: = \frac{d}{d}$

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• Where ¢ is the wave length of the light D is separation between the screen and the slits. D is the the sepration Between the slits.

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$\sf \longrightarrow \beta \: \infty \: \frac{1}{d}$

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$\sf \: \therefore \: \frac{ \beta }{ \beta } = \frac{d}{d}$

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$\sf \longrightarrow or \: \beta \: = \frac{d}{3d} \: \beta$

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$\sf \longrightarrow \frac{ \beta }{3}$

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Answer 2

$\underline{ \underline{\huge \pink{\mathbb{ANSWER}}}}$

Given :

• The Distance between slits is 3

Let the new fringes width β

so,

$\bold{so \: \: \beta ' = \frac{ \gamma d}{3d} = \frac{1}{3} \beta }$

Therefore fringe width also became ⅓ times.