Plzzzz help me in the problem................
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According to Archimedes' principle, when an object is wholly or partially immersed in a liquid, it experiences a buoyant force which is equal to the weight of liquid displaced by the object. The buoyant force acting on the ball, F = Volume of the ball × density of water × acceleration due to gravity Volume of the ball =Mass of the ball/ Density of the ball =4 kg/4000 kg/m3 =0.001m3 The buoyant force acting on the ball, F = 0.001m3 × 1000 kg/m3 × 10 m/s2 F = 10 N The buoyant force acting on the ball = 10 N
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Given :-
- Weight of ball = 4 kg
- Density of ball = 4000 kgm³
- Density of water= 1000 kgm³
Buoyant Force = ?
- The buoyant force is given as
- F = ρgV
- F = 4/4000 × 10 × 1000 = 10
- So, buoyant force will be 10 N
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Buoyant : -
- Buoyant force is an upward force exerted by a fluid, which opposes the weight of an object in the fluid. Objects immersed in water observes a loss in weight due to the buoyant force.
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