Question

Plzzzz help me in the problem................​

Answer 1

$\huge \bf \colorbox{pink}{Answer}$

According to Archimedes' principle, when an object is wholly or partially immersed in a liquid, it experiences a buoyant force which is equal to the weight of liquid displaced by the object. The buoyant force acting on the ball, F = Volume of the ball × density of water × acceleration due to gravity Volume of the ball =Mass of the ball/ Density of the ball                           =4 kg/4000 kg/m3                           =0.001m3  The buoyant force acting on the ball, F = 0.001m3 × 1000 kg/m3 × 10 m/s2 F = 10 N The buoyant force acting on the ball = 10 N

Answer 2

$\Large\bold{\underline{\underline{Answer:-}}}$

Given :-

• Weight of ball = 4 kg
• Density of ball = 4000 kgm³
• Density of water= 1000 kgm³

Buoyant Force = ?

$\rule{200}{4}$

$\bf\small\bold{\underline{\underline{Step-By-Step\:Explanation:-}}}$

• The buoyant force is given as
• F = ρgV
• F = 4/4000 × 10 × 1000 = 10
• So, buoyant force will be 10 N

____________________________

Buoyant : -

• Buoyant force is an upward force exerted by a fluid, which opposes the weight of an object in the fluid. Objects immersed in water observes a loss in weight due to the buoyant force.