Question

plzzzz help me out....... ​

Answer 1

Answer:-

• The distance covered by the mass in 10 s is 10 m.

Given :-

• A mass of 5 kg is acted upon by a force of 1 N starting from rest.

To find :-

• How much is distance covered by th mass in 10 s.

Solution :-

• Mass (m) = 5 kg
• Force (F) = 1 N

Now find the acceleration.

★ Formula used :-

${\boxed{\sf{F=ma}}}$

[ Put values ]

$: \implies \sf \: 1 = 5 \times a \\ \\ : \implies \sf \: 1 = 5a \\ \\ : \implies \sf \: a = \dfrac{1}{5} \\ \\ : \implies \sf \: a = 0.2$

Then the acceleration is 0.2 m/s².

★ Formula used :-

${\boxed{\sf{s=ut+\dfrac{1}{2}at^2}}}$

• u = 0 m/s
• a = 0.2 m/s²
• t = 10 sec

[Put values]

$: \implies \sf \: s = 0 \times t + \dfrac{1}{2} \times 0.2 \times {10}^{2} \\ \\ : \implies \sf \: s = 0 + \dfrac{1}{2} \times 0.2 \times 100 \\ \\ : \implies \sf \: s = 10$

•Hence, the distance covered by the mass in 10 s is 10 m.

Answer 2

Answer:

Using Newton's second law , F=ma, we get the acceleration to be

$0.2 \: m/ \: {s}^{2}$

now we know that

$s \: = \: ut \: + \frac{1}{2} \: {at}^{2}$

$u \: = \: 0, \: t \: = \: 10s \: , \: a = 0.2 \: m/ {s}^{2}$

$\therefore \: s = \frac{1}{2} * \: 0.2 \: * \: {10}^{2} = 10m$

hope this helps you