Question

plzzzz help me plzzz​

Answer 1

Step-by-step explanation:

(i) In ΔABC:

⇒ ∠ACB + ∠CBA + ∠BAC = 180°

(ii) In ΔADC:

⇒ ∠ACD + ∠CDA + ∠DAC = 180°

On solving (i) & (ii), we get

⇒ ∠ACB + ∠CBA + ∠BAC = ∠ACD + ∠CDA + ∠DAC

⇒ ∠ACD + ∠DCB + ∠CBA + ∠DAC + ∠DAB = ∠ACD + ∠CDA + ∠DAC

⇒ ∠DCB + ∠CBA + ∠DAB = ∠CDA

⇒ ∠CDA = ∠C + ∠B + ∠C

⇒ ∠ADC = ∠A + ∠B + ∠C

Hope it helps!

Answer 2

The answer is explained