Question

plzzzz help with this problem

Answer 1

total mass =250
mass of water=90
hence loss=90/250)×100
os=9000/250
=36℅

Answer 2

Given: Cuso(4) * 5H(2)O - > CuSO(4) + 5H(2)O

Hydrated copper = CuSO(4).5H(2)O

= > 64 + 32 + 16 * 4  + 5(2 * 1 + 16)

= > 96 + 64 + 90

= > 250.


DeHydrated copper sulphate = CuSO(4)

= > 64 + 32 +  16 * 4

= > 64 + 32 + 64

= > 160


Now,

Difference in molecular weights = 250 - 160

                                                      = 90


% Loss = 90/250 * 100

            = 36%.



Hope this helps!