Question

plzzzz kal mera exam hai...

Answer 1

LHS = (sinA-cosA+1)/(sinA+cos-1)
= (1 + sinA) (1 - sinA)/cos A(1 - sinA)
= 1 - sin2A/cos A(1 - sinA)
= cos2A/cos A(1 - sinA)
= cosA/(1 - sinA)
= 1/ (1/cosA - sinA/cosA)
= 1/(secA - tanA) = RHS
Hence Proved

Answer 2

heya friends!!!

from lhs

=>sin¢-cos¢-1
---------------------.
sin¢+cos¢-1. ● 【dividing by cos¢ on numerator and denomenator 】

then we get.....

tan¢-1+sec¢
=>--------------------
tan¢+1-sec¢

=>tan¢+sec¢-1
--------------------------------------------
tan¢+(sec^2¢-tan^2¢ ) -sec¢. ◆since.. 【sec^2¢-tan^2¢=1 】

*(tan¢+sec¢-1)
=>-----------------------------------
(sec¢-tan¢¢)(tan¢ +sec¢-1)

◆【here sec¢+tan¢-1 is common in denomenator 】●since it is cancelled here

remaining

=>1/sec¢-tan¢

hence Rhs .

1/sec¢-tan¢..Rhs .....prooved ...

hope it help you.

@rajukumar☺☺☺