Question

plzzzz prove it I'll give u 50 points​

Answer 1

hope it helps plz mark brainliest

Answer 2

Formulas used :

cot θ = cos θ / sin θ

tan θ = sin θ / cos θ

a³ - b³ = ( a - b )( a² + ab + b² )

( 1 + cot θ + tan θ )( sin θ - cos θ )

⇒ ( 1 + cos θ / sin θ + sin θ / cos θ ) ( sin θ - cos θ )

⇒ ( sin θ cos θ + sin²θ + cos²θ )( sin θ - cos θ ) / sin θ cos θ

⇒ ( sin³θ - cos³θ ) / sin θ cos θ

⇒ ( 1/cosec³θ - 1/sec³θ ) / sin θ cos θ

⇒ ( sec³θ - cosec³θ ) / sec³θcos³θ / sec θ cos θ

⇒ ( sec³θ - cosec³θ ) / sec²θcosec²θ