PlZzzz solve 13 question
Attachments:

Answers
Answered by
1
for upward motion:
u=49m/s
v=0m/s (at maximum height, v becomes zero)
g= -9.8m/s
now applying newtons 3rd eq. of motion
v^2-u^2 = -2gh
putting the values..
we get
h=122.5m
now
for 2nd part
downward motion:
u=0
h=122.5m
t=?
applying 2nd eq.
s=ut +1/2gt^2 here g can be taken positive
putting values
t^2= 25
t=5s
u=49m/s
v=0m/s (at maximum height, v becomes zero)
g= -9.8m/s
now applying newtons 3rd eq. of motion
v^2-u^2 = -2gh
putting the values..
we get
h=122.5m
now
for 2nd part
downward motion:
u=0
h=122.5m
t=?
applying 2nd eq.
s=ut +1/2gt^2 here g can be taken positive
putting values
t^2= 25
t=5s
riddhimahada:
thax
Similar questions
India Languages,
10 months ago
Chemistry,
10 months ago
English,
10 months ago
Social Sciences,
1 year ago
Chemistry,
1 year ago
Science,
1 year ago
Physics,
1 year ago