Question

PlZzzz solve 13 question

Answer 1

for upward motion:
u=49m/s
v=0m/s (at maximum height, v becomes zero)
g= -9.8m/s
now applying newtons 3rd eq. of motion
v^2-u^2 = -2gh
putting the values..
we get
h=122.5m
now
for 2nd part
downward motion:
u=0
h=122.5m
t=?
applying 2nd eq.
s=ut +1/2gt^2 here g can be taken positive

putting values
t^2= 25
t=5s