plzzzz solve 4 part
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(PQ)^2+(QR)^2=(RP)^2
(3X)^2+(4X)^2=(5X)^2
9X^2+16X^2=25X^2
√9X^2+16X^2=√25X^2 sq. root both the sides
3x+4x=5x
where, 3, 4 and 5 are Pythagorean triplets......
thus, we can conclude that,
triangle pqr is a right angled triangle...
hence proved ..
please mark as brainliest....
PLZZZZ ..
(3X)^2+(4X)^2=(5X)^2
9X^2+16X^2=25X^2
√9X^2+16X^2=√25X^2 sq. root both the sides
3x+4x=5x
where, 3, 4 and 5 are Pythagorean triplets......
thus, we can conclude that,
triangle pqr is a right angled triangle...
hence proved ..
please mark as brainliest....
PLZZZZ ..
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