asked by adityaevil, 10 days ago

# plzzzz solve it..........​

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## Answers

Answered by TheDivineSoul
20

## Thereforevolumealsowillbetripled..I.e.C.15l

Thank you..

Answered by omsamarth4315
67

Answer:

## twocases:-

• first :- if molar mass of gases are neglected .

• second :- if molar mass of gases are not neglected .

• MM of nitrogen = 14 .

• MM of Carbon dioxide = 12 + (2×16) = 12 + 32 = 44 .

_______________________________________

## Case1:-(MMneglected):-

given molecules of nitrogen gas :- 10²³ .

given molecules of carbon dioxide gas :- 3 × 10²³ .

therefore , volume will be 3 times .

• i. e , volume will be 3 × 5 L

• = 15 L

• hence, option c .

_______________________________________

## Case2:-(MMisnotneglected):-

we know ,

• MM of Nitrogen is 14 .

• MM of CO2 is 44

ratio of molar masses :- 44/14 = 3 . 14

• therefore, volume will be 3.14 × 5 L

• 15.70 L ( option d )
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