Question

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Answer 1

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Height of tower is 30m. What is length of shadow of tower when angle of inclination of sun is 30° ?

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Length of shadow of tower = 30√3 m.

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$\large\underline{\underline{\sf{\maltese\:\: \red{Given \: : }}}}$

✯ Height of tower (AB) = 30 m

✯ Angle of inclination of sun (∠ACB ) = 30°

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✯Length of shadow of tower (BC) = ?

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$\large\underline{\underline{\sf{\maltese\:\: \red{Solution \: : }}}}$

In ∆ ABC,

✪ AB = Height of tower = 30 m

✪ ∠ACB = Angle of inclination of sun = 30°

✪ BC = Length of shadow of tower = ?

Let's use Trigonometry Ratios now.

In order to find Length of shadow of tower(BC) we need to use tan or cot.

I am using here tan you can also use cot. The answer won't vary.

$\rm tan \: C = \frac{AB}{BC}$

$\implies \rm tan\: 30^\circ = \frac{30\: m}{BC}$

$\implies\rm \frac{1}{\sqrt{3}} = \frac{30\: m}{BC}$

$\implies \rm BC = 30 m\: \times \: \sqrt{3}$

$\implies \rm BC = 30\sqrt{3} \: m$

∴ Length of shadow of tower = 30√3 m.

Answer 2

Answer:

Solution

In ∆ ABC,

✪ AB = Height of tower = 30 m

✪ ∠ACB = Angle of inclination of sun = 30°

✪ BC = Length of shadow of tower = ?

Let's use Trigonometry Ratios now.

In order to find Length of shadow of tower(BC) we need to use tan or cot.

I am using here tan you can also use cot. The answer won't vary.

$\rm tan \: C = \frac{AB}{BC}$

$\implies \rm tan\: 30^\circ = \frac{30\: m}{BC}$

$\implies\rm \frac{1}{\sqrt{3}} = \frac{30\: m}{BC}$

$\implies \rm BC = 30 m\: \times \: \sqrt{3}$

$\implies \rm BC = 30\sqrt{3} \: m$

∴ Length of shadow of tower = 30√3 m.