Question

Plzzzz solve it..... ​

Answer 1

Answer:

Sine, Cosine and Tangent

Sine Function: sin(θ) = Opposite / Hypotenuse

Cosine Function: cos(θ) = Adjacent / Hypotenuse

Tangent Function: tan(θ) = Opposite0

Answer 2

${\mathfrak{\underline{\orange{\:\:\: Given:-\:\:\:}}}}$

$\:\:\:\:\bullet\:\:\:\sf{Initial \:velocity\: (u) = 40 \:m/s}$

$\:\:\:\:\bullet\:\:\:\sf{Final \:velocity \:(v) = 0 \:m/s}$

$\:\:\:\:\bullet\:\:\:\sf{Time \:(t) = 10 \:seconds}$

${\mathfrak{\underline{\pink{\:\:\:To \:Find:-\:\:\:}}}}$

$\:\:\:\:\bullet\:\:\:\sf{Distance \ covered \ by \ vehicle \ before \ it \ stop}$

${\mathfrak{\underline{\purple{\:\:\: Calculation:-\:\:\:}}}}$

☯ Firstly, We'll find acceleration:—

$\dashrightarrow\:\: \sf{v = u + at}$

$\dashrightarrow\:\: \sf{0 = 40 + a \times 10 }$

$\dashrightarrow\:\: \sf{- 40 = 10a }$

$\dashrightarrow\:\: \sf{ \dfrac{ \cancel{- 40}}{\cancel{10}} = a}$

$\dashrightarrow\:\: \sf{a = - 4 \: m /{s}^{2} }$

☯ Now, Calculate the distance covered:—

$\dashrightarrow\:\: \sf{{v}^{2} = {u}^{2} + 2as }$

$\dashrightarrow\:\: \sf{{0}^{2} = {40}^{2} + 2 \times ( - 4) \times s }$

$\dashrightarrow\:\: \sf{ - 1600 = - 8s}$

$\dashrightarrow\:\: \sf{\dfrac{ \cancel{ - 1600}}{ \cancel{- 8}} = s }$

$\dashrightarrow\:\: {\boxed{\bf{s = 200 \: m }}}$

${\mathfrak{\underline{\purple{\:\:\:Additional \:Information:-\:\:\:}}}}$

☢ Equations Of Motion:—

$\boxed{</p><p></p><p>\begin{minipage}{3 cm} \\</p><p></p><p>\sf{\:\bullet\:\:v = u +at} \\ \\</p><p></p><p>\sf{\:\bullet\:\:s = ut + \frac{1}{2}\:at^{2} }\\ \\</p><p></p><p>\sf{\:\bullet\:\:v^{2} = u^{2} + 2as}\\ \\</p><p>\sf{\:\bullet\:\:s = \dfrac{1}{2} (u + v)t}\\ </p><p></p><p>\end{minipage}</p><p></p><p>}$

$\sf{Where,}$

$\:\:\:\:\bullet\:\:\:\textsf{v = Final velocity}$

$\:\:\:\:\bullet\:\:\:\textsf{u = Initial velocity}$

$\:\:\:\:\bullet\:\:\:\textsf{a = Acceleration}$

$\:\:\:\:\bullet\:\:\:\textsf{s = Distance}$

$\:\:\:\:\bullet\:\:\:\textsf{t = Time taken}$