Question

plzzzz solve it by coorect way specily 9th class

Answer 1

(a-b)^3=a^3 - b^3 - 3ab(a-b)
(6a - b)^3=216a^3 - b^3 - 18ab(6a-b)
=216a^3 - b^3 - 108a^2b + 18ab^2
(6a - b)^3 is the answer

Answer 2

Given Equation is 216a^3 - b^3 - 108a^2b + 18ab^2

= > (6a)^3 - b^3 - (3)(6a)^2(b) + (3)(6a)(b)^2

It is in the form of a^3 - b^3 - 3a^2b + 3ab^2, Here a = 6a. b = b

We know that a^3 - b^3 - 3a^2b + 3ab^2 = (a - b)^3.

= > (6a - b)^3.



Hope this helps!