Question

plzzzz solve plzzz..........

Answer 1

see the equation given in picture,.
clearly,
6 moles of water needed to produce 4 moles of phosphoric acid,.or we can say that .
to produce 4 moles of phosphoric acid we need 6moles of water..
.
to produce 1 moles of phosphoric acid we need 6/4 moles of water
.
.to produce 10moles of phosphoric acid we need (6/4)*10= 15 moles of water

...now we know that ,.
there are two grams of hydrogen in one mole of water.
..or we can say,.
1mole of water has 2grams of hydrogen.,
therefore 15 moles of hydrogen has 15*2=30 grams of hydrogen!!!!....
Hence 30grams of hydrogen are needed to produce 10moles of phosphoric acid......
ANS.30gm...
hope this helps you!!!!!..

.

Answer 2

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HERE IS YOUR ANSWER ☞
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Rxn involved in preparation of H3PO4 is =>

$p _{4 \: (s)} + 6h _{2}o _{(l)} = = = > \: 4h_{3}po_{4(aq)}$

thus,

there is involvent of H2O (water) as a reactant and not Hydrogen.

Thus,

amount of H2O used for 10 moles of H3PO4 is :-

=> 10 moles H3PO4 used ------> 6 moles H2O

then,

=> 10 moles of H3PO4 -------> 6/4 × 10 moles of H2O

= 15 moles of H2O

1 moles of H2O = 18 gm

then,

15 moles of H2O = 15×18 = 270 gm of H2O

NOW,

if we see,

preparation of H2O

$2h_{2} + o_{2} = = > \: 2h_{2}o$

=> 1 moles of H2 -----> 1 mole of H2O

=> 15 mole of H2 ----> 15 moles of H2O

and,

=> 1 moles of H2 = 2 gm

=> 15 moles of H2 = 30 gm ___________________"ANSWER"

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HOPE IT WILL HELP YOU ☺☺
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