plzzzz solve question no.4 plzzz
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formula for the sum of infinite geometric progression: a/1-r= 4The sequence which consist of cubes is geometric progression in itself. so the first term will be= a³ and common ratio r³
the equation will be a³/1-r³=192
dividing both the equationsa²/ 1+r+r²= 48
now this equation can be expressed as: a= 4 (1-r)
substituting in the above equation4² (1-r)²/ 1+r +r² = 48(1-r)²= 3(1+r+r²)1-2r +r² = 3r² + 3r + 3
i hope it will help u golu bro....
the equation will be a³/1-r³=192
dividing both the equationsa²/ 1+r+r²= 48
now this equation can be expressed as: a= 4 (1-r)
substituting in the above equation4² (1-r)²/ 1+r +r² = 48(1-r)²= 3(1+r+r²)1-2r +r² = 3r² + 3r + 3
i hope it will help u golu bro....
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