Question

Plzzzz solve them faaast

Answer 1

question1)

question1)|A|=3 ,|B|=4,|c|=6

a) find max. value and minimum values of

|a+b-c|

solution:-Here ,it's very important to, understand,that,mod only shows the magnitude,....

if |A|=3....then it means,that the magnitude of that vector is eqaul to 3.Whether it is positive or negative is not fixed..

If we take,VectorA and VectorB as negative

then

|A+B-C|=|-3-4-6|=13

this will be the maximum value,coz,it is the sum of all three......

now, let's think on minimum value

If vectorA and Vector B will be taken as positive

then

|A+B-C|=|3+4-6|=1

|A+B-C|=|3+4-6|=1This will be the minimum value....

b)If vectorA ,vectorB,vectorC are mutually perpendicular,then find|A+B-2C|

Solution:-If the three vectors(x,y,z) are perpendicular then the sum of their magnitude=(x^2+y^2+z^2)^1/2

here

x=A=3

y=B=4,z=-2c=-2×6=12(-)

magnitude=(9+16+14)^1/2=(169)^1/2=13

c)can(|A+2B+C|=0?

solution:-

minimum value which can be possible

|A+2B+C|=|-3+4×2-6|=1

minimum value will be1

minimum value will be1 hence 0 can't be possible