Math, asked by ad5105046, 10 months ago

plzzzz solve this ....​

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Answers

Answered by liyutsazirange99
1

Answer:

(root 3 + 1 / root 3 - 1)*(root 3 + 1 /root 3 + 1)

(root 3 + 1)^2/(root3)^2 - (1)^2

(root 3)^2 + (1)^2 + 2* root 3*1 / 3-1

3 + 1 + (2*root 3)/2

4 + (2root3)/2

(4)/2 + (2root3)/2

2 + (root 3)

a = 2

b = 1

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