plzzzz.solve this 6th one...fastly guys.
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Heya,
Given:∆ABC~∆DEF and Ar(ABC):AR(DEF)=1:2
To find:DE
Ar(ABC)/Ar(DEF)=AB^2/DE^2
=>1/2=(4)^2/DE^2
=>DE^2=32
=>DE=√32=4√2.
HOPE IT HELPS U?!!!:-}
Given:∆ABC~∆DEF and Ar(ABC):AR(DEF)=1:2
To find:DE
Ar(ABC)/Ar(DEF)=AB^2/DE^2
=>1/2=(4)^2/DE^2
=>DE^2=32
=>DE=√32=4√2.
HOPE IT HELPS U?!!!:-}
sanikapatil10:
thanks kartik u are brainllist student
its ans is 4√2 this is na it is right na yarr its statement also
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Δabc and ΔDEF are equilateral triangle
ΔABC~ΔDEF (by SSS)
=> AB=DE=BC=EF=AC=DF
=>DE=4
ΔABC~ΔDEF (by SSS)
=> AB=DE=BC=EF=AC=DF
=>DE=4
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