Question

plzzzz.solve this 6th one...fastly guys.​

Answer 1

Heya,

Given:∆ABC~∆DEF and Ar(ABC):AR(DEF)=1:2


To find:DE

Ar(ABC)/Ar(DEF)=AB^2/DE^2

=>1/2=(4)^2/DE^2

=>DE^2=32

=>DE=√32=4√2.


HOPE IT HELPS U?!!!:-}

Answer 2

Δabc and ΔDEF are equilateral triangle
ΔABC~ΔDEF (by SSS)
=> AB=DE=BC=EF=AC=DF
=>DE=4