Question

plzzzz solve this properly​

Answer 1

QUESTION:

(a² + 3ab + b²) ÷ (a+b)

ANSWER:

(a² + 3ab + b²) ÷ (a+b) = 1

GIVEN:

a = 1

b = 0

METHOD 1:

EXPLANATION:

Substitute a = 1 and b = 0 in (a² + 3ab + b²) ÷ (a+b)

(a² + 3ab + b²) ÷ (a+b) = (1² + 3(1)(0) + 0²) ÷ ( 1+0)

(a² + 3ab + b²) ÷ (a+b) = (1 + 0 + 0)/1

(a² + 3ab + b²) ÷ (a+b) = 1

METHOD 2:

IDENTITY USED:

A² + 2AB + B² = (A + B)²

EXPLANATION:

(a² + 3ab + b²) ÷ (a+b) = (a² + 2ab + b² + ab) ÷ (a+b)

(a² + 3ab + b²) ÷ (a+b) = ((a + b)² + ab) ÷ a + b

Substitute a = 1 and b = 0 in ((a + b)² + ab) ÷ (a + b)

(a² + 3ab + b²) ÷ (a+b) = ( (1+0)² + 1(0) ) ÷ (1 + 0)

(a² + 3ab + b²) ÷ (a+b) = (1 + 0 )/1

(a² + 3ab + b²) ÷ (a+b) = 1

NOTE:

• PREFER METHOD 1 IN MULTIPLE CHOICE QUESTIONS(MCQs) OR ONE WORDS

• PREFER METHOD 2 IN TWO MARK QUESTIONS OR OTHER HIGHER MARKS