Question

plzzzz solve this question.........​

Answer 1

Step-by-step explanation:

Given A. P is 10,16,22

a=t1=10, t2=16, t3=22.

common difference (d) =t2-t1=16-10=6

we know,

tn=a+(n-1)×d

when tn=128

128=10+(n-1)×6

128-10=6n-6

118=6n-6

118+4=6n

124=6n

Therefore

n= 124/6

hence, 128 is not a term in the given A. P

hope you understand

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