Question

plzzzz solve this question urgently .

Answer 1

Sol : ( 1 / 4 )^(-2 )  - 3 x 8^0 - ( 1 / 64 )^ ( - 1 / 2 )

 Using identity , { ( 1 / a )^( - m ) = a^m }

= ( 4 )² - 3 x 8^0 - ( 64 )^( 1 /2 )

 Using identity { a^0 = 1 }

 = 16 - 3 x 1 - ( 64 )^(1/2 )

 Using identity , { a^( 1 / 2 ) = √a }

 = 16 - 3 - √64

 = 16 - 3 - 8

 = 16 - 11

 = 5.

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Answer 2

..........answer = 5