Question

plzzzz solve this!!!
very much urgent ▶▶▶▶​

Answer 1

$\text{Initial velocity of train:} 50kmph\\</p><p>u= \frac{250}{18}\text{m/sec} = \frac{125}{9} m/s. \\</p><p>\mathrm{Acceleration}= -0.5 \mathrm{m/s^2}=a\\</p><p>\mathrm{Final \: velocity}=0 \mathrm{m/s.}=v$

Using:

$</p><p>v^2= u^2+2as\\</p><p>0=\frac{125^2}{9^2}+2(-0.5)s\\</p><p>s=(\frac{125}{9})^2=192.9m$