Question

PLZZZZ SOLVE TIHS QUESTION A body A is dropped from a height h1= 80 m above the ground. At the same time another body B is fired from the top of a tower of height
h2 = 20 m at an angle alpha to the horizontal as shown. If the two collide in mid air, find the value of tan​

Answer 1

Answer:

Tan=4°

Explanation:

h1=80m

h2=20m

d=15m

h=h1-h2

h=80-20

 =60m

tan= h/d

tan=60/15

tan=4 degree

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Answer 2

Answer:

When the two collide in mid-air then the value of tanα will be 4°.

Explanation:

We are given in the question,

h₁=80m

h₂=20m

and distance between the two towers(d)=15m

Let the horizontal distance between tower A and B at the height of 20 m from the top of tower B be 15 m i.e. d,

Height of tower A above 20 m from the ground will be

H =h₁-h₂=80m-20m=60m

And we know that,

tanα=perpendicular$/$base        (1)

Here perpendicular distance will be the height of tower A above 20 m from the surface ground i.e.60m and the base will be the horizontal distance of tower A at the height of 20m from tower B.i.e.15m.

Let's substitute the values in equation (1) we get;

tanα=60m$/$15m=4°

Hence, we conclude that when the two collide in mid-air then the value of tanα will be 4°.