Plzzzz tell me notes of maths class 6 chapter 11 algebra
Answers
Introduction to Algebra
●The study of numbers is called Arithmetic.
●The study of shapes is called Geometry.
●The study to use the letters and symbol in mathematics is called Algebra.
Algebra
Algebra is a part of mathematics in which the letter and symbols are used to represent numbers in equations. It helps us to study about unknown quantities.
Example:-
How many matchsticks will be used in the 50th figure?
Solution:-
3n + 1
3 × 50 + 1
= 151 matchsticks
The Idea of a Variable
Variable refers to the unknown quantities that can change or vary and are represented using the lowercase letter of the English alphabets.
One such example of the same is the rule that we used in the matchstick pattern
3n + 1
Here the value of n is unknown and it can vary from time to time.
More Examples of Variables
●We can use any letter as a variable, but only lowercase English alphabets.
●Numbers cannot be used for the variable as they have a fixed value.
●They can also help in solving some other problems.
Example: 1
Karan wanted to buy story books from a bookstall. She wanted to buy 3 books for herself, 2 for her brother and 4 for 2 of her friends. Each book cost Rs.15.how much money she should pay to the shopkeeper?
Solution: 1
Cost of 1 book = Rs.15
We need to find the cost of 9 books.
Therefore,
Cost of 9 books = 15 × 9
= 135
Therefore Karan needs to pay Rs.135 to the shopkeeper of the bookstall.
The variable and constant not only multiply with each other but also can be added or subtracted, based on the situation.
Example: 2
Manu has 2 erasers more than Tanu. Form an expression for the statement.
Solution: 2.1
Erasers that Tanu have can be represented using a variable (x)
Erasers that Manu have = erasers that Tanu have + 2
Erasers with Manu = x + 2
Solution: 2.2
Erasers that Manu have can be represented using a variable (y)
Erasers that Tanu has = erasers that Manu have - 2
Erasers with Tanu = y - 2
Use of Variables in Common Rules (Geometry)
1. Perimeter of Square
The perimeter of a square = Sum of all sides
= 4 × side
= 4s
Thus, p = 4s
Here s is variable, so the perimeter changes as the value of side change.
2. Perimeter of Rectangle
Perimeter of rectangle = 2(length + breadth)
= 2 (l + b) or 2l + 2b
Thus, p + 2 × (l + b) or 2l + 2b
Where, l and b are variable and the value of perimeter changes with the change in l and b.
Use of Variables in Common Rules (Arithmetic)
1. Commutativity of Addition
5 + 4 = 9
4 + 5 = 9
Thus, 5 + 4 = 4 + 5
This is the commutative property of addition of the numbers, in which the result remains the same even if we interchanged the numbers.
a + b = b + a
Here, a and b are different variables.
Example
a = 16 and b = 20
According to commutative property
16 + 20 = 20 + 16
36 = 36
2. Commutativity of Multiplication
8 × 2 = 16
2 × 8 = 16
Thus, 8 × 2 = 2 × 8
This is the commutative property of multiplication, in which the result remains the same even if we interchange the numbers.
a × b = b × a
Here, a and b are different variables.
Example
18 ×12 = 216, 12 ×18 = 216
Thus, 18 × 12 = 12 × 18
3. Distributivity of Numbers
6 × 32
It is a complex sum but there is an easy way to solve it. It is known as the distributivity of multiplication over the addition of numbers.
6 × (30 + 2)
= 180 + 12
= 192
Thus, 6 × 32 = 192
A × (b + c) = a × b + a × c
Here, a, b and c are different variables.
4. Associativity of Addition
This property states that the result of the numbers added will remain same regardless of their grouping.
(a + b) + c = a + (b + c)
Example
(4 + 2) + 7 = 4 + (2 + 7)
6 + 7 = 4 + 9
13 = 13
Expressions
Arithmetic expressions may use numbers and all operations like addition, subtraction, multiplication and division.
Example
Find 3x – 12 if x = 6
Solution
(3 × 6) – 12
= 18 – 12
= 5
Thus,
3x – 12 = 5
Practical use of Expressions
Example
3 boys go to the theatre. The cost of the ticket and popcorn is $33 and $15 respectively. What is the cost per person?
Solution
Let’s say,
x = cost of ticket per person
y = cost of popcorn/person
Total cost of the movie (ticket + popcorn) per person = x + y
Total cost of ticket + popcorn for 3 boys = 3(x + y)
= 3 (33 + 15)
= 3 (48)
= 144
Hence the total cost of movie ticket and popcorn for 3 boys is $144.
Equation
If we use the equal sign between two expressions then they form an equation.
An equation satisfies only for a particular value of the variable.
The equal sign says that the LHS is equal to the RHS and the value of a variable which makes them equal is the only solution of that equation.
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