Question

plzzzzźzzzz answer this​

Answer 1

Answer:

Given:

• $x^3 + 3x^2 + 3x + 1 ÷ x+4$
• $Remainder = ?$

Solution:

$x+ 4 = 0$

$\implies x = -4$

$p(x) = x^3 + 3x^2 + 3x + 1$

$p(-4) = (-4)^3 + 3(-4)^2 + 3(-4) + 1$

$p(-4) = -64 + 48 - 12 + 1$

$p(-4) = 49 - 76$

$\boxed{\implies{\boxed{Remainder =- 27}}}$

Answer 2

Answer:

Take the answer and write it