Question

plzzzzx solveeeeeeeeee​

Answer 1

$\bf \huge {\underline {\underline \red{AnSwEr}}}$

$\bf {\underline {\underline \pink{Divide}}}$

$\bf \implies \frac{ {9m}^{5} + {12m}^{4} - {6m}^{2} }{ \sqrt{3} {m}^{2} }$

$\bf \implies \frac{ {m}^{2} ( {9m}^{5} + 12 {m}^{4} - {6m}^{2} )}{ \sqrt{3} }$

$\bf \implies \frac{ {9m}^{7} + {12m}^{6} - {6m}^{4} }{ \sqrt{3} }$

$\bf Multiply \: the \: faction \: by \frac{ \sqrt{3} }{ \sqrt{3} }$

$\bf \implies \frac{ {9m}^{7} + {12m}^{6} - {6m}^{4} }{ \sqrt{3} } \times \frac{ \sqrt{3} }{ \sqrt{3} }$

$\bf \implies \frac{( {9m}^{7} + {12m}^{6} - {6m}^{4} \sqrt{3} }{ \sqrt{3} \sqrt{3} }$

$\bf \implies \frac{3( {3m}^{7} + {4m}^{6} - {2m}^{4} \sqrt{3} }{ \sqrt{3} }$

$\bf \implies( {3m}^{7} + {4m}^{6} - {2m}^{4} ) \sqrt{3}$

$\bf \implies 3 \sqrt{3} {m}^{7} + 4 \sqrt{3} {m}^{6} - 2 \sqrt{3} {m}^{4}$

$\bf {\underline {\underline \pink{Evaluate}}}$

$\bf \implies \frac{ {z}^{2} + 3z - 10 }{z - 2}$

$\bf \implies \frac{ {z}^{2} + 5z - 2z - 10 }{z - 2}$

$\bf \implies \frac{ {z}^{2}(z + 5) - 2(z + 5) }{z - 2}$

$\bf \implies \frac{(z + 5)(z - 2)}{z - 2}$

$\bf \implies z + 5$

Answer 2

$\huge {\underline {\underline \pink{ƛƝƧƜЄƦ}}}$

$\huge {\mathcal {\underline {\underline {\purple {Divide}}}}}$

$\bf \implies {9m}^{5} + {12m}^{4} - {6m}^{2} \div \sqrt{3} {m}^{2}$

$\bf \implies \frac{ {9m}^{5} + {12m}^{4} - {6m}^{4} }{ \sqrt{3} {m}^{2} }$

$\bf \implies \frac{ {m}^{2}( {9m}^{5} + {12m}^{6} - {6m}^{4} )}{ \sqrt{3} }$

$\bf Multiply \: the \: faction \: by \frac{ \sqrt{3} }{ \sqrt{3} }$

$\bf \implies \frac{ ( {9m}^{7} + {12m}^{6} - {6m}^{4} )}{ \sqrt{3} } \times \frac{ \sqrt{3} }{ \sqrt{3} }$

$\bf \implies \frac{( {9m}^{7} + {12m}^{6} - {6m}^{4}) \sqrt{3} }{ \sqrt{3} \sqrt{3} }$

$\bf \implies \frac{3( {3m}^{7} + {4m}^{6} - {2m}^{4}) \sqrt{3} }{ 3 }$

$\bf \implies ( {3m}^{7} + {4m}^{6} - {2m}^{4} ) \sqrt{3}$

$\bf \implies 3 \sqrt{3} {m}^{7} + 4 \sqrt{3} {m}^{6} - 2 \sqrt{3} {m}^{4}$

$\huge {\mathcal {\underline {\underline {\purple {Evaluate}}}}}$

$\bf \implies \frac{ {z}^{2} + 3z - 10}{z - 2}$

$\bf \implies \frac{ {z}^{2} + 5z + 2z - 10 }{z - 2}$

$\bf \implies \frac{z(z + 5) - 2(z + 5)}{z - 2}$

$\bf \implies \frac{(z + 5)(z - 2)}{z - 2}$

$\bf \implies z + 5$