Question

plzzzzz answer kal test h mera​

Answer 1

just put the value given of x or y in equation. if it satisfies the eq. i.e it becomes 0 then it is a zero of eq. that is it is a root of it

Answer 2

Answer:

$f(x) = 2 - 5x \\ putting \: x = \frac{2}{5} \\ f(x) = 2 - 5 \times \frac{2}{5} \\ 2 - 2 \\ = 0 \\ yes. \frac{2}{5} is \: a \: zero \: of \: p(x) \\ \\ g(y) = 2y + 1 \\ putting = y = \frac{ - 1}{2} \\ g(y) = 2 \times ( \frac{ - 1}{2} ) + 1 \\ - 1 + 1 \\ = 0 \\ yes. \frac{ - 1}{2} is \: a \: zero \: of \: p(x)$