plzzzzz Answer these Questions.....
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The given vector has components of 3, 1, respectively in the x and y directions. To determine its length we require it’s projection in the x-y plane. For this the x and y components should be sufficient.
It’s magnitude or length in a given plane is determined by:
x2+y2−−−−−−√x2+y2
where x and y denote the x and y components respectively.
Plugging in the values, the output obtained is:
32+12−−−−−−√32+12
which is:
3.16227766017
hope so it will help you my friend.
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