Math, asked by AshwaniDalal, 1 year ago

plzzzzz answer this question

today is my maths exam​

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Answered by Anonymous
2

Answer:

Length of arc = 10π cm    ( ≈ 31.4 cm, approx )

Angle at centre = π / 3  radians

Step-by-step explanation:

Let the 30 cm chord be AB and let O be the centre of the circle.

As the diameter is 60 cm, the radius is 30 cm.

Therefore all three sides of triangle OAB are 30 cm, so this triangle is equilateral.

It follows that the angle subtended at the centre by the minor arc AB is

∠AOB = 60° = 60 × π / 180 radians = π / 3  radians.

The length of the minor arc is:

(60/360) × circumference of circle

= 1/6 × 2πr

= πr / 3

= π × 30 cm / 3

= 10π cm

≈ 31.4 cm

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