plzzzzz give me correct ans and plzzzzz give fast answer it's urgent
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here 's your answer
see the attachment
see the attachment
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raj3778:
from where you found BC=AB
radii of same circle bro
but that's a line segment which far from the radii of quadrant
I dont know bro but you tell me the ans in comment i am waiting
I have answered
can you see that
? plz
tell me bro
22 whole 3/7cm^2 is the answer
you know of which books this question is?
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Given:A trapezium ABCD in which BC=4 cm, AD=10 cm and AD//BC as well as angle DAB a right angled triangle.
Cons:Draw a line CF//AB so that AB is equal to CF and BC is equal to AFequal 4 cm therefore DF is equal 6cm.
1/2×(10+4)×height CF=24.5cm^2
7h=24.5cm^2
h=3.5cm
now,taking radius 3.5/2 of the quadrant ,we get,1 upon 4 ×Pie ×r^2 is equal to
1/4x22/7×(35/20)^2
77/32cm^2
now,area of shaded region equal area of trapezium - area of quadrant =24.5cm^2-77/32cm^2
707/32=22 whole 3/7cm^2
Cons:Draw a line CF//AB so that AB is equal to CF and BC is equal to AFequal 4 cm therefore DF is equal 6cm.
1/2×(10+4)×height CF=24.5cm^2
7h=24.5cm^2
h=3.5cm
now,taking radius 3.5/2 of the quadrant ,we get,1 upon 4 ×Pie ×r^2 is equal to
1/4x22/7×(35/20)^2
77/32cm^2
now,area of shaded region equal area of trapezium - area of quadrant =24.5cm^2-77/32cm^2
707/32=22 whole 3/7cm^2
plz mark it as the brainliest answer
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