Question

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Answer 1

Question :

Calculate number of atoms in the following

(I) 1g of Au

(II) 1g of Na

(III) 1g of Li

Answer :

★ Method to solve :

First of all we need to find number of moles of each element$.$

We know that one mole of element contains 6.022 × 10²³ atoms. Therefore we will multiply number of moles with 6.022 × 10²³ in order to find number of atoms in the given amount of element.

⧪ No. of atoms in 1g of Au :

➠ Moles = 1/100 = 0.01

No. of atoms = 0.01 × 6.022 × 10²³

• N = 6.022 × 10²¹ __ (I)

⧪ No. of atoms in 1g of Na :

➠ Moles = 1/23 = 0.043

No. of atoms = 0.043 × 6.022 × 10²³

• N = 2.6 × 10²² __ (II)

⧪ No. of atoms in 1g of Li :

➠ Moles = 1/7 = 0.14

No. of atoms = 0.14 × 6.022 × 10²³

• N = 8.6 × 10²² __ (III)

Answer 2

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➦Your answer is in the attachment.

★ Method we used to solve :

First of all we need to find number of moles of each element

We know that one mole of element contains 6.022 × 10²³ atoms. Therefore we will multiply number of moles with 6.022 × 10²³ in order to find number of atoms in the given amount of element.

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➠Stay happy N Blessed