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will mark as brainliest plzzzzz help......
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angle ABC is 90 since AB is the diameterand you might know if angle is constructed by connecting a point to the circle from a diameter then it is 90 rest you can use Pythagoras theorem and then you can apply the area of circle and area of triangle thank you
and yes I have applied pi r square by 2 sin a b is the diameter that divide the circle into two parts thank you now this is the brainliest answer please
and yes I have applied pi r square by 2 sin a b is the diameter that divide the circle into two parts thank you now this is the brainliest answer please
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Since ∠ACB is subtended by diameter,∠ACB=90°
Using Pythagoras theorem,
AB=√(24²+10²)=26
r=26/2=13cm
Area of semicircle=πr²/2=3.14*13*13/2
=265.33cm²
Shaded area=Area of semicircle- Area of ∆le
=265.33-(24*10/2)
=265.33-120
=145.33cm²
Using Pythagoras theorem,
AB=√(24²+10²)=26
r=26/2=13cm
Area of semicircle=πr²/2=3.14*13*13/2
=265.33cm²
Shaded area=Area of semicircle- Area of ∆le
=265.33-(24*10/2)
=265.33-120
=145.33cm²
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