Question

plzzzzz help me....​

Answer 1

Given:-

Wavelength of A = $4 \times {10}^{ - 5}$

Mass of B= 25% of mass of A

Velocity of B = 50% of velocity of A

━━━━━━━━━━━━━━━━

Need to find:-

Wavelength of B=?

━━━━━━━━━━━━━━━━

Solution:-

We know,

$\lambda \: = \dfrac{h}{mv}$

${\lambda}_{A} = \dfrac{h}{{m}_{A} \times {v}_{A}}$

$\bold{\purple{\boxed{4 \times {10}^{ - 5} = \dfrac{h}{{m}_{A} \times {v}_{A}}}}}$

━━━━━━━━━━━

Now let's find mass of B,

${m}_{B} = 25 \: {m}_{A}$

$\purple{\bold{\boxed{{m}_{B} = \dfrac{25}{100} {m}_{A}}}}$

━━━━━━━━━━━

Velocity of B,

${v}_{B} = 50 \: {v}_{A}$

$\boxed{\purple{\bold{ {v}_{B} = \dfrac{50}{100} {v}_{A}}}}$

━━━━━━━━━━━

Now,

${\lambda}_{B} = \dfrac{h}{{m}_{B} \times {v}_{B}}$

$= \dfrac{h}{ \dfrac{25}{100}{m}_{A} \times \dfrac{50}{100}{v}_{A} }$

$= \dfrac{h}{ \dfrac{{m}_{A}}{4} \times \dfrac{{v}_{A}}{2} }$

$= \dfrac{8h}{{m}_{A} \times {v}_{A}}$

$= 8 \times (4 \times {10}^{ - 5} )$

$\red{\bold{\boxed{\boxed{\large{= 32 \times {10}^{ - 5} m}}}}}$

Answer 2

Given:-

Wavelength of A = $4 \times {10}^{ - 5}$

Mass of B= 25% of mass of A

Velocity of B = 50% of velocity of A

━━━━━━━━━━━━━━━━

Need to find:-

Wavelength of B=?

━━━━━━━━━━━━━━━━

Solution:-

We know,

$\lambda \: = \dfrac{h}{mv}$

${\lambda}_{A} = \dfrac{h}{{m}_{A} \times {v}_{A}}$

$\bold{\red{\boxed{4 \times {10}^{ - 5} = \dfrac{h}{{m}_{A} \times {v}_{A}}}}}$

━━━━━━━━━━━

Now let's find mass of B,

${m}_{B} = 25 \: {m}_{A}$

$\orange{\bold{\boxed{{m}_{B} = \dfrac{25}{100} {m}_{A}}}}$

━━━━━━━━━━━

Velocity of B,

${v}_{B} = 50 \: {v}_{A}$

$\boxed{\blue{\bold{ {v}_{B} = \dfrac{50}{100} {v}_{A}}}}$

━━━━━━━━━━━

Now,

${\lambda}_{B} = \dfrac{h}{{m}_{B} \times {v}_{B}}$

$= \dfrac{h}{ \dfrac{25}{100}{m}_{A} \times \dfrac{50}{100}{v}_{A} }$

$= \dfrac{h}{ \dfrac{{m}_{A}}{4} \times \dfrac{{v}_{A}}{2} }$

$= \dfrac{8h}{{m}_{A} \times {v}_{A}}$

$= 8 \times (4 \times {10}^{ - 5} )$

$\green{\bold{\boxed{\boxed{\large{= 32 \times {10}^{ - 5} m}}}}}$