Math, asked by nan57, 4 months ago

plzzzzz help me out.......... ​

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Answers

Answered by BrainlyEmpire
11

\sf{\underline{\boxed{\purple{\large{\bold{ Solution}}}}}}

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\sf { \left[\begin{array}{cc}2x &x \\y &3y \end{array}\right] \: \:  \left[\begin{array}{cc}3\\2\end{array}\right] =  \left[\begin{array}{cc}16 \\9\end{array}\right]}

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\sf  \left[\begin{array}{cc}2x\times 3 &x \times 2 \\y\times 3 &3y\times 2 \end{array}\right] \: \:  =  \left[\begin{array}{cc}16 \\9\end{array}\right]

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\sf  \left[\begin{array}{cc}6x & +2x \\3y &+ 6y \end{array}\right] \: \:  =  \left[\begin{array}{cc}16 \\9\end{array}\right]

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\sf  \left[\begin{array}{cc}8x \\ 9y \end{array}\right] \: \:  =  \left[\begin{array}{cc}16 \\9\end{array}\right]

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Now ;

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8x = 16

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x = 16 / 8

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x = 2

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\sf{\red{\boxed{\bold{x = 2 }}}}

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9y = 9

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y = 9/ 9

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y = 1

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\sf{\red{\boxed{\bold{y = 1}}}}

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Answered by Anonymous
0

Answer:

\sf{\underline{\boxed{\purple{\large{\bold{ Solution}}}}}}

Solution

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\begin{gathered}\sf { \left[\begin{array}{cc}2x &x \\y &3y \end{array}\right] \: \: \left[\begin{array}{cc}3\\2\end{array}\right] = \left[\begin{array}{cc}16 \\9\end{array}\right]}\end{gathered}

[

2x

y

x

3y

][

3

2

]=[

16

9

]

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\begin{gathered}\sf \left[\begin{array}{cc}2x\times 3 &x \times 2 \\y\times 3 &3y\times 2 \end{array}\right] \: \: = \left[\begin{array}{cc}16 \\9\end{array}\right]\end{gathered}

[

2x×3

y×3

x×2

3y×2

]=[

16

9

]

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\begin{gathered}\sf \left[\begin{array}{cc}6x & +2x \\3y &+ 6y \end{array}\right] \: \: = \left[\begin{array}{cc}16 \\9\end{array}\right]\end{gathered}

[

6x

3y

+2x

+6y

]=[

16

9

]

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\begin{gathered}\sf \left[\begin{array}{cc}8x \\ 9y \end{array}\right] \: \: = \left[\begin{array}{cc}16 \\9\end{array}\right]\end{gathered}

[

8x

9y

]=[

16

9

]

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Now ;

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8x = 16

⠀⠀⠀⠀

x = 16 / 8

⠀⠀⠀⠀

x = 2

⠀⠀⠀⠀

\sf{\red{\boxed{\bold{x = 2 }}}}

x=2

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9y = 9

⠀⠀⠀⠀

y = 9/ 9

⠀⠀⠀⠀

y = 1

⠀⠀⠀⠀

\sf{\red{\boxed{\bold{y = 1}}}}

y=1

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