Question

plzzzzz help me out..... ​

Answer 1

Answer:-

$\bf{ \boxed{⟹ \frac{2}{3} , \frac{3}{4} , \frac{4}{5} }}$

Proof:-

$\sf \red{ \underline {\underline {correct \: question \ \: : }}}$

$\sf{arrange \: in \: ascending \: order}$

$\sf{ \frac{2}{3} , \frac{4}{5} ,\frac{3}{4} }$

$\sf \red{ \underline {\underline {note\ \: : }}}$

$\sf \: if \: we \: need \: to \: arrange \: these$

$\sf{in \: ascending \: order}. \: we \: need$

$\sf \: equalise \: the \: denominator$

$\sf \red{ \underline {\underline {let \: us \: solve \ \: : }}}$

$\sf{lcm \: of \: 3.5.4 \: is \: 60}$

$\bf{⟹ \frac{2}{3} \times \frac{20}{20} = \frac{40}{60} }$

$\bf⟹ \frac{4}{5} \times \frac{12}{12} = \frac{48}{60}$

$\bf⟹ \frac{3}{4} \times \frac{15}{15} = \frac{45}{60}$

$\sf \blue{let \: us \: arrange \: this \: in \: order}$

$\sf40 > 45 > 48$

$\bf{ \boxed{⟹ \frac{40}{60} , \frac{45}{60} , \frac{48}{60} }}$

Answer 2

Answer:

Answer:-

$\bf{ \boxed{⟹ \frac{2}{3} , \frac{3}{4} , \frac{4}{5} }}$

Proof:-

$\sf \red{ \underline {\underline {correct \: question \ \: : }}}$

$\sf{arrange \: in \: ascending \: order}$

$\sf{ \frac{2}{3} , \frac{4}{5} ,\frac{3}{4} }$

$\sf \red{ \underline {\underline {note\ \: : }}}$

$\sf \: if \: we \: need \: to \: arrange \: these$

$\sf{in \: ascending \: order}. \: we \: need$

$\sf \: equalise \: the \: denominator$

$\sf \red{ \underline {\underline {let \: us \: solve \ \: : }}}$

$\sf{lcm \: of \: 3.5.4 \: is \: 60}$

$\bf{⟹ \frac{2}{3} \times \frac{20}{20} = \frac{40}{60} }$

$\bf⟹ \frac{4}{5} \times \frac{12}{12} = \frac{48}{60}$

$\bf⟹ \frac{3}{4} \times \frac{15}{15} = \frac{45}{60}$

$\sf \blue{let \: us \: arrange \: this \: in \: order}$

$\sf40 > 45 > 48$

$\bf{ \boxed{⟹ \frac{40}{60} , \frac{45}{60} , \frac{48}{60} }}$