Question

plzzzzz help me out..... ​

Answer 1

GIVEN :-

• The denominator of a number is greater than its numerator by 7 .
• If numerator is increased by 19 and denominator by 3 , then the new number becomes 4 .

To Find :-

• The Original number .

SOLUTION :-

️ Let,

• The numerator be “x”
• So, the denominator be “(x + 7)” .

✴️ According to question,

• Numerator is increased by “19” and denominator is decreased by “3” .

▼ So now ,

• Numerator is “x + 19”
• Denominator is “x + 19 - 7” = “x + 4” .

✴️ New rational number is,

$\rm{\pink{\boxed{\dfrac{x\:+\:19}{x\:+\:4}}}}$

✴️ Again, Given that the New number becomes “4” .

$\rm{\implies\:\dfrac{x\:+\:19}{x\:+\:4}\:=\:4\:}$

$\rm{\implies\:(x\:+\:19)\:=\:4(x\:+\:4)\:}$

$\rm{\implies\:x\:=\:1\:}$

️ Therefore,

• Numerator of the numerical number is “1” .
• Denominator of the numerical number is “x + 7” = “8” .

$\bigstar\:\bf{\underline{\blue{\boxed{Original\:number\:is\:\:\dfrac{1}{8}\:}}}}$

Answer 2

Answer:

let  a/b is the fraction,

b-8=a

b=a+8

a+17/b-1=3/2

a+17/a+8-1=3/2

a+17/a+7=3/2

2a+34=3a+21

34-21=3a-2a

13=a

a+8=b

13+8=b

21=b

the fraction is  13/21

hope this helps you