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Is the magnitude of electric field 3000 N/C?
If yes then
we know flux=E*A*cosx where x is angle between vector E and vector A
In first case, flux = 3000*(0.1)² = 30 as x=0 cosx = 1
in second case, x=90-60=30. cos30=√3/2
flux= 3000*(0.1)² * √3/2= 15√3
If yes then
we know flux=E*A*cosx where x is angle between vector E and vector A
In first case, flux = 3000*(0.1)² = 30 as x=0 cosx = 1
in second case, x=90-60=30. cos30=√3/2
flux= 3000*(0.1)² * √3/2= 15√3
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