PLZZZZZ SOLVE IT.. ITS ICSE 10TH QSTN... PLZZZZ
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I think the answer is 58degree
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From figure :
∠PSQ = 90°.
Also,
∠SPR=1/2 ∠ROS.
(Angle at the centre is double the angle at the circumference subtended by the same chord).
Now,
SPT =1/2 * 42°= 21°
∴ In right triangle PST,
∠PTS = 90° - ∠SPT
⇒ ∠RTS = 90°- 21° = 69°
Hope it helps!
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