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Given that:-
=> First term , a = 5
=>Last term ,l = an = 45
=>Sum of n terms ,Sn = 400
=>Number of terms , n =?
=>Common difference , d = ?
Solution :-
=> We know that sum of n terms,
=>Sn = n/2 (a+1)
=>400 = n/2(5+45) (By substituting)
=>400=n/2(50)
=>n =16.
Now,
=> l = a+(n-1)d
=>45 = 5 +(16-1)d
=>40 = 15d
=> d = 40/15
=>d = 8/3.
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