plzzzzz solve this sum
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Step-by-step explanation:
Given A line cuts two sides AB and AC of triangle ABC at points P and Q respectively. we have to prove that
\frac{Area(APQ)}{Area(ABC)}=\frac{AP\times AQ}{AB\times AC}
By area formula i.e
ar(APQ)=\frac{1}{2}AP\times AQsinA
ar(ABC)=\frac{1}{2}AB\times ACsinA
∴ \frac{Area(APQ)}{Area(ABC)}=\frac{\frac{1}{2}AP\times AQsinA}{\frac{1}{2}AB\times ACsinA}
=\frac{AP\times AQ}{AB\times AC}
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