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Step-by-step explanation:
(x+1)(x+4) = x^2+5x+4
(x+2)(x+3) = x^2+5x+6
let us consider ,
x^2+5x = a
so , (a+4)(a+6)= 120
a^2+10a+ 24=120
a^2+10a=96
a^2+10a-96=0
a^2+16a-6a-96 =0
(a+16)(a-6)=0
so a= -16 or +6
-16 is discriminant so a =+6
x^2+5x = 6
x^2+5x-6=0
x^2+6x-x-6=0
(x-1)(x+6)=0
so x=+1
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