Question

Plzzzzzz give
solution ​

Answer 1

Answer:

x = -1/2

Step-by-step explanation:

two zeros are -√3 and √3

x = - √3; x = √3

$x = - \sqrt{3} \: \: \: \: \: \: \: \: \: \: x = \sqrt{3} \\ x + \sqrt{3} = 0 \: \: \: \: \: x - \sqrt{3} = 0 \\ multiply \: (x + \sqrt{3} )(x - \sqrt{3} ) \\ = {x }^{2} - { (\sqrt{3}) }^{2} \\ = {x}^{2} - 3$

$divide \: the \: cubic \: polynomial \: by \: ( {x}^{2} - 3) \\ \frac{2 {x}^{3} + {x}^{2} - 6x - 3 }{ {x}^{2} - 3 } \\ = 2x + 1 \\ \\ 2x + 1 = 0 \\ 2x = - 1 \\ x = - \frac{1}{2}$

therefore the other zero is -1/2

hope you get your answer