Plzzzzzz help guys
Find the value of K,so that k+2,4k-6,3k+2 are three consecutive terms of an A.P.
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Answer:
k+2 ,4k-6 .3k+2 are in AP
a + c/2 =b
k+2+3k+2 /2 =4k-6
4k+4 /2=4k-6
2k+2 =4k-6
4k -2k =2 +6
2k =8
k=4
hope this helps u.....
EshaTrivedi:
is "a+c/2=b" a formula??
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I hope this will help you.......✌️✌️✌️✌️✌️✌️
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