plzzzzzz plzzzzzz solve this question god for sake!!!!
Attachments:
Answers
Answered by
1
Answer:
AREA OF FIGURE 19.54 IS 12 cm^2
AND AREA OF FIGURE 19.55 IS 253 cm^2
Step-by-step explanation:
I AM SENDING THE SOLUTION PLEASE GO THROUGH IT AND PLEASE LIKE IT
FOR FIGURE 19.54
AREA OF THE SHADED REGION
= AREA OF PARALLELOGRAM ABDE
= BASE × HEIGHT
= ED × BE
= 3 × 4 cm^2
= 12 cm^2
CONSTRUCTION IN TGE THE FIGURE 19.55 : DRAW A PERPENDICULAR HP FROM H ON CD SUCH THAT AHPC IS A RECTANGLE
FOR FIGURE 19.55
AREA OF THE SHADED REGION
= AREA OF TRIANGLE ABC + AREA OF RECTANGLE AHPC + AREA OF SQUARE GFDP + AREA OF TRIANGLE FED
= 25 + 180 + 36 + 12 cm^2
= 253 cm^2
Similar questions