Math, asked by ariba345, 11 months ago

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Answered by swattik32
1

Answer:

AREA OF FIGURE 19.54 IS 12 cm^2

AND AREA OF FIGURE 19.55 IS 253 cm^2

Step-by-step explanation:

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FOR FIGURE 19.54

AREA OF THE SHADED REGION

= AREA OF PARALLELOGRAM ABDE

= BASE × HEIGHT

= ED × BE

= 3 × 4 cm^2

= 12 cm^2

CONSTRUCTION IN TGE THE FIGURE 19.55 : DRAW A PERPENDICULAR HP FROM H ON CD SUCH THAT AHPC IS A RECTANGLE

FOR FIGURE 19.55

AREA OF THE SHADED REGION

= AREA OF TRIANGLE ABC + AREA OF RECTANGLE AHPC + AREA OF SQUARE GFDP + AREA OF TRIANGLE FED

= 25 + 180 + 36 + 12 cm^2

= 253 cm^2

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