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panditadityadubey:
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(ii) Since, the graph is straight line passing throgh the origin, so current is directly proportional to the potential difference.
Hence, the ratio V/I remains constant.
From graph,
when V=1.5 V
I= 0.6 amp
so, V/I = 1.5/0.6 = 2.5 ohm
For p.d. 0.8, 1.2 and 1.6 V, the value of V/I ratio remains the same, i.e, 2.5 ohm.
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