Question

plzzzzzzz help me brainliest

Answer 1

Answer:

in Δ abd

tan45° =ab/bd

1 =100/bd

bd =100

in Δ abc

tan 30° =ab/bc

1/√3 =100 /bc

bc =100 ×√3

=100 ×1.732

bc =173.2

distance between the two cars is

bc -bd

173.2 -100

=73.2

Answer 2

Let distance between cars be xm

In ABD

Tan45=AB/BD

1=100/y

y=100m

In ABC

Tan30=100/100+x

I√3=100/100+x

100+x=100√3

X=100√3-100

x=100(1.732-1)

X=100×0.732

X=73.2m